5x^(2/3)-34x^(1/3)-7=0

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Solution for 5x^(2/3)-34x^(1/3)-7=0 equation: 


x in (-oo:+oo)

5*x^(2/3)-(34*x^(1/3))-7 = 0

5*x^(2/3)-34*x^(1/3)-7 = 0

t_1 = x^(1/3)

5*t_1^2-34*t_1^1-7 = 0

5*t_1^2-34*t_1-7 = 0

DELTA = (-34)^2-(-7*4*5)

DELTA = 1296

DELTA > 0

t_1 = (1296^(1/2)+34)/(2*5) or t_1 = (34-1296^(1/2))/(2*5)

t_1 = 7 or t_1 = -1/5

t_1 = -1/5

x^(1/3)+1/5 = 0

1*x^(1/3) = -1/5 // : 1

x^(1/3) = -1/5

( -1/5 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 7

x^(1/3)-7 = 0

1*x^(1/3) = 7 // : 1

x^(1/3) = 7

x^(1/3) = 7 // ^ 3

x = 343

x = 343

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